关于数组IFS 设置问题.求大神指点

qimuzhi

1. #!/bin/bash -
   
2. 
   
3. OLD_IFS="$IFS"
   
4. IFS=","
   
5. arr=(
   
6. a,
   
7. bb bb,
   
8. cccc
   
9. )
   
10. for s in ${arr[@]}
    
11. do
    
12.     echo "$s"
    
13. done
    
14. IFS="$OLD_IFS"

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=============实际的输出==============

1. ~/tmp/shell/ifs $ ./a.sh
   
2. a
   
3. 
   
4. bb
   
5. bb
   
6. 
   
7. cccc
   
8. ~/tmp/shell/ifs $

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=============OUT==============

我想要的是:
=============OUT==============
a
bb bb
cccc
=============OUT==============

求大神指点,我想以逗号为数组的分隔符号,但是不行.这是为什么啊?

扯淡的青春要扯淡对待

bash中应该不支持二维数组吧，，
+ LD_IFS='
'
+ IFS=',
'
+ arr=(a, bb bb, cccc)
+ for s in '${arr[@]}'
+ echo a
a
+ for s in '${arr[@]}'
+ echo ''

+ for s in '${arr[@]}'
+ echo bb
bb
+ for s in '${arr[@]}'
+ echo bb
bb
+ for s in '${arr[@]}'
+ echo ''

+ for s in '${arr[@]}'
+ echo cccc
cccc
+ IFS=

要实现以上结果：
LD_IFS=$IFS
IFS=$',\n'
mm="
a,
bb bb,
cccc
"
arr=($mm)
for s in ${arr[@]}
do
    echo "$s"
done
IFS="$OLD_IFS"

yjh777

IFS 不会影响 () 里面的分割解析;

用 read -a :
    IFS="," read -a a <<< "a,bb bb,cccc"