函数参数使用**dict 会报错

hmchzb19

这个代码是可以跑的。

1. import smtplib
   
2. from email.mime.text import MIMEText
   
3. from email.mime.base import MIMEBase
   
4. from email.mime.multipart import MIMEMultipart
   
5. 
   
6. from email.utils import COMMASPACE,formatdate
   
7. from email import encoders
   
8. 
   
9. #charset.add_charset('utf-8', charset.QP, charset.QP)
   
10. def my_send_mail(subject,message,from_addr,*to_addrs,headers):
    
11.     email=MIMEText(message,"plain",_charset="utf-8")
    
12.     #email=MIMEMultipart()
    
13.     assert type(headers)==dict
    
14.     email['subject']=subject
    
15.     email['From']=from_addr
    
16.     headers=headers.copy()
    
17.     for (header,value) in headers.items():
    
18.         email[header]=value
    
19.    
    
20.     host="localhost"
    
21.     port=1025
    
22.     sender=smtplib.SMTP(host,port)
    
23.     for addr in to_addrs:
    
24.         del email['To']
    
25.         email['To']=addr
    
26.         email['Date']=formatdate(localtime=True)
    
27.         
    
28.         sender.sendmail(from_addr,addr,email.as_string())
    
29.     sender.quit()
    
30. 
    
31. 
    
32. headers={"Reply-To":"me2@exmaple.com"}
    
33. my_send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com",headers=headers)
    

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下面的代码就不能执行，会报错。

1. def send_mail(subject,message,from_addr,*to_addrs,**headers):
   
2.     email=MIMEText(message,"plain",_charset="utf-8")
   
3.     #email=MIMEMultipart()
   
4.     assert type(headers)==dict
   
5.     email['subject']=subject
   
6.     email['From']=from_addr
   
7.     headers=headers.copy()
   
8.     for (header,value) in headers.items():
   
9.         email[header]=value
   
10.    
    
11.     host="localhost"
    
12.     port=1025
    
13.     sender=smtplib.SMTP(host,port)
    
14.     for addr in to_addrs:
    
15.         del email['To']
    
16.         email['To']=addr
    
17.         email['Date']=formatdate(localtime=True)
    
18.         
    
19.         sender.sendmail(from_addr,addr,email.as_string())
    
20.     sender.quit()
    
21. 
    
22. send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com",{"Reply-To":"me2@exmaple.com"})

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调用语句可以这么写：

1. send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com",**{'Reply-To':'me2@exmaple.com'})

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不能使用

1. send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com","Reply-To"="me2@exmaple.com")

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Linux_manne

1. 不是应该传这样的么？
   
2. "Reply-To" ＝ "me2@exmaple.com"

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hmchzb19

回复 2# Linux_manne

1.     send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com",'Reply-To'='me2@exmaple.com')
   
2.                                                                                                              ^
   
3. SyntaxError: keyword can't be an expression
   

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Linux_manne

回复 3# hmchzb19


   哦,  那就用** unpacking 吧

shou55

send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com","Reply-To"="me2@exmaple.com")

请改成

send_mail("A model subject","The message contents","from@example.com","to1@example.com","to2@exmaple.com",Reply-To="me2@exmaple.com")

最后一个Reply-To不要用双引号引起来.